Smallest lexicographical value of a string
By : englobo
Date : March 29 2020, 07:55 AM
Does that help The empty string is the "smallest" of all strings  that is, it compares less than any nonempty string. §21.4.8.4 [string::op<]: code :
template<class charT, class traits, class Allocator>
bool operator< (const basic_string<charT,traits,Allocator>& lhs,
const basic_string<charT,traits,Allocator>& rhs) noexcept;
int compare(const basic_string& str) const noexcept;
Condition Return Value
size() < str.size() < 0
size() == str.size() 0
size() > str.size() > 0

How to get the smallest in lexicographical order?
By : vdv9dv
Date : March 29 2020, 07:55 AM
around this issue The smallest lexicographical order is an order relation where string s is smaller than t, given the first character of s (s1) is smaller than the first character of t (t1), or in case they are equivalent, the second character, etc. So aaabbb is smaller than aaac because although the first three characters are equal, the fourth character b is smaller than the fourth character c. code :
cbacdcbc = adbc
cbacdcbc = adcb
cbacdcbc = badc
cbacdcbc = badc
...

How to remove duplicate letters while preserving the smallest lexicographical order
By : Yang Li
Date : March 29 2020, 07:55 AM
I wish this helpful for you First, let's create a set of all distinct letters of the string s. The size of this set is the length of the answer and the number of steps in our algorithm. We will add one letter to the answer on each step with the following greedy approach: On every step iterate through the remaining letters in alphabetical order and for every letter l: code :
public String removeDuplicateLetters(String s) {
StringBuilder result = new StringBuilder();
int[] subsets = new int[s.length()];
int subset = 0;
for (int i = s.length()  1; i >= 0; i) {
char ch = s.charAt(i);
subset = addToSet(subset, ch);
subsets[i] = subset;
}
int curPos = 0;
while (subset != 0) {
for (char ch = 'a'; ch <= 'z'; ++ch) {
if (inSet(subset, ch)) {
int chPos = s.indexOf(ch, curPos);
if (includes(subsets[chPos], subset)) {
result.append(ch);
subset = removeFromSet(subset, ch);
curPos = chPos + 1;
break;
}
}
}
}
return result.toString();
}
private boolean inSet(int set, char ch) {
return (set & (1 << (ch  'a'))) != 0;
}
private boolean includes(int set, int subset) {
return (set  subset) == set;
}
private int addToSet(int set, char ch) {
return set  (1 << (ch  'a'));
}
private int removeFromSet(int set, char ch) {
return set & ~(1 << (ch  'a'));
}

lexicographical create largest and smallest substring
By : user3715836
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further problem statement: , I presume you are talking about the following: code :
for (int i = 1; i <= s.length()  k; i++) { //This line
String str = "abcdefghij";
int k = 4;
for (int i = 0; i <= str.length()  k; i++) {
System.out.println(str.substring(i,i+k));
}

Select lexicographical smallest string after duplicates removed
By : Habib Ahmad
Date : March 29 2020, 07:55 AM
should help you out Algorithm Check which letters are present in the input string: a,b,c,d. Find the first a that has all of b,c,d after it.

