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How to get a certain word in string of getline?


How to get a certain word in string of getline?

By : Valeriy Karkachev
Date : November 20 2020, 11:01 PM
this will help this is definition of getline function: istream& getline (istream& is, string& str, char delim);
Delim is a delimitier which stops getline from reading the stream after to the given character. so you can do something like this:
code :
string trash;
string properline;

getline(file, trash, '\t');
getline(file, trash, '\t'); //second tab, still trash
getline(file, properline);


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Why is getline() in C++ not working? (no matching function for call to 'getline(std::ofstream&, std::string&)'

Why is getline() in C++ not working? (no matching function for call to 'getline(std::ofstream&, std::string&)'


By : Naomi Green
Date : March 29 2020, 07:55 AM
I hope this helps . std::getline is designed for use with input stream classes (std::basic_istream) so you should be using the std::ifstream class:
code :
std::ifstream file("test.txt");
while ( std::getline(file, line) )
{
    std::cout << line << std::endl;
}
C++: Why won't getline() print the last word of the input string?

C++: Why won't getline() print the last word of the input string?


By : Coder
Date : March 29 2020, 07:55 AM
wish of those help getline didn't skip the last word. It's still waiting for you to finish it. You selected the space character (' ') as the delimiter, so getline is going to read until if finds a space (not a tab or a newline), or until the input stream ends. Your loop isn't going to stop at the end of the line either, like you seem to be expecting. It is going to keep reading until the stream ends.
If you want to read a single line, and then separate the line word by word, then just call getline once, with the \n delimiter (which is the default). Then use an istringstream to separate the resulting string word by word.
code :
std::string line;
std::getline(in, line);
std::istringstreaam iss(line);
std::string content;
while (iss >> content)
    std::cout << content << std::endl;
how to do a word count from getline?

how to do a word count from getline?


By : A.J. Schmitz
Date : March 29 2020, 07:55 AM
With these it helps So i am trying to get the word count from the getline function, but i keep getting a segmentation fault error. Here, you can assume that white space will only be defined as '\t', '\n', and ' '.
code :
while(ptr[i]!= ' ' || ptr[i]!= '\t' || ptr[i] != '\n'){
size_t mystringlen = strlen(mystring);

...

if (ptr[i]!= ' ' && ptr[i]!= '\t' && ptr[i] != '\n') {
    ++word;
    while(i < mystringlen && ptr[i]!= ' ' && ptr[i]!= '\t' && ptr[i] != '\n'){

...
if (!isspace(ptr[i])) {
    ++word;
    while(i < mystringlen && !isspace(ptr[i])){
g++ insists looking to stdio.h getline instead of std::getline (string)

g++ insists looking to stdio.h getline instead of std::getline (string)


By : lenya
Date : March 29 2020, 07:55 AM
To fix the issue you can do Your problem is inputFile is const in read_input_file. inputFile needs to be modified by getline so there is no overload that takes an const ifstream&. Unfortunately the compiler, by being helpful and showing you other possible overloads, doesn't make you aware of this fact.
Why is sequence [getLine, getLine, getLine] not evaluated lazily?

Why is sequence [getLine, getLine, getLine] not evaluated lazily?


By : Daniela T
Date : March 29 2020, 07:55 AM
To fix this issue getContents is lazy, getLine isn't. Lazy IO isn't a feature of Haskell per se, it's a feature of some particular IO actions.
code :
do a
   b
do
    input <- do
       input <- concat ( map (fmap (:[])) [getLine, getLine, getLine] )
       return input
    mapM_ print input
do 
  input <- do
    x <- getLine
    y <- getLine
    z <- getLine
    return [x,y,z]
  mapM_ print input
sequence [] = return []
sequence (a:as) = do
  x <- a
  fmap (x:) $ sequence as
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