By : Duongquoc Viet
Date : November 20 2020, 11:01 PM

may help you . I'm a beginner in C and I've been trying to code a Quicksort program that can take a randomly generated array of real numbers and its size as its argument, and then sorts the elements in ascending order. I cannot figure out what to put in the array size field in the first recursive call of the function QuickSort, which is meant to represent the subarray A[0...q1]. As far as I can tell, the rest of the code is fine because when linked to a driver program that generates the random numbers, the program returns the elements, albeit in the incorrect order. I appreciate any help/suggestions. , You're only problem is you seem to confuse: code :
A[i]=something;
#include<stdio.h>
int Partition(float *,int);
void QuickSort(float *A,int n) {
int q;
if(n>1){
q = Partition(A,n);
QuickSort(A,q); //Trying to figure out what to put in here.
QuickSort(A+q+1,(nq1)); //This recursion sends the subarray A[q+1...n1] to QuickSort, I think it works fine.
}
}
int Partition(float *A,int n){
int i,j;
float x;
float tmp;
x = A[n1];
i=0;
for(j=0;j<=n2;j++){
if(A[j] <= x){
tmp = A[i];
A[i]=A[j];
A[j]=tmp;
i = i+1;
}
}
tmp = A[i];
A[i]=A[n1];
A[n1]=tmp;
return i;
}
int main() {
float A[] = {3, 4, 5, 10, 21, 9, 1, 7, 8, 10};
QuickSort(A,10);
for(int i = 0; i < 10; i ++)
printf("%f ",A[i]);
return 0;
}
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cost of partitioning in quicksort
By : Роман Дубинка
Date : March 29 2020, 07:55 AM

Quicksort with 2 way partitioning
By : user3634425
Date : March 29 2020, 07:55 AM

Quicksort partitioning
By : Nedved31
Date : March 29 2020, 07:55 AM
To fix the issue you can do EDIT My previous answer seemed to fix the issue but wasn't correct. code :
t = a[i];
a[i++] = a[j];
a[j] = t; // added a decrement here

Why is the pivot element moved to the first or last position of the array before partitioning in Quicksort?
By : Lumimuut
Date : March 29 2020, 07:55 AM
help you fix your problem The Hoare partition scheme is similar in concept to the example in the question, except that the initial pivot value can be taken from any place within the array, and no special end case swapping is performed, as the pivot value and pivot pointer will end up in it's correct position during the Hoare partitioning. Here is an example of quicksort that uses median of 3, Hoare partition scheme, exclusion of elements adjacent to and equal to pivot (they are already sorted), and only using recursion on the smaller partition to limit worst case stack space to O(log(n)). code :
void QuickSort(uint32_t a[], size_t lo, size_t hi) {
while(lo < hi){
size_t i = lo, j = (lo+hi)/2, k = hi;
uint32_t p;
if (a[k] < a[i]) // median of 3
std::swap(a[k], a[i]);
if (a[j] < a[i])
std::swap(a[j], a[i]);
if (a[k] < a[j])
std::swap(a[k], a[j]);
p = a[j];
i; // Hoare partition
k++;
while (1) {
while (a[++i] < p);
while (a[k] > p);
if (i >= k)
break;
std::swap(a[i], a[k]);
}
i = k++;
// at this point, a[i] or a[k] or both == p (pivot value)
while(i > lo && a[i] == p) // exclude middle values == pivot
i;
while(k < hi && a[k] == p)
k++;
// recurse on smaller part, loop on larger part
if((i  lo) <= (hi  k)){
QuickSort(a, lo, i);
lo = k;
} else {
QuickSort(a, k, hi);
hi = i;
}
}
}

quicksort help, not sure why partitioning returns index and not array
By : Yannick Winters
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , The index that has been returned is only there to identify the end of recurrsion within the QuickSort algorithm. It's mainly the index of the pivot element that is used to identify the smaller and bigger numbers. AND: You are referring to an enhanced Quick Search Algorithm. In the basic version of the QuickSearch algorithm the returned index won't be needed.



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