By : Kidson Fung
Date : November 20 2020, 11:01 PM

wish help you to fix your issue It is fine if you encode with binary. But you probably need to add another layer (or a filter) depending on your task and model. Because your encoding now implicates invalid shared features due to the binary representation. For example, a binary encoding for input (x = [x1, x2]): code :
'apple' = [0, 0]
'orange' = [0, 1]
'table' = [1, 0]
'chair' = [1, 1]
'fruit' = 0
'furniture' = 1
(argmin W) Loss = y  (w1 * x1 + w2 * x2 + b)
(argmin U,W) Loss = y  (u1 * (w1 * x1 + w2 * x2 + b) +
u2 * (w1 * x1 + w2 * x2 + b) +
b2)
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Why program not returning binary numbers in Text.txt as it's copying binary numbers from Image.jpeg
By : humdrum75
Date : March 29 2020, 07:55 AM
help you fix your problem Well, it could be because you are reading data from "Image.jpeg" and not "Desert.jpeg". It could also be that you are writing to "Text.txt" and not "text.txt". I could also be that you are copying the jpeg image data byte for byte, and that will be interpreted as text by your text editing program, rather than as 'binary' as you suggest. What I really want to know is, what did you expect to see in the text file? code :
try
{
FileInputStream fr=new FileInputStream("Image.jpeg");
FileOutputStream fr1=new FileOutputStream("Text.txt");
PrintWriter out = new PrintWriter(fr1);
int temp=0;
while((temp=fr.read())!=1)
{
out.write(Integer.toBinaryString(temp) + " ");
}
out.close();
fr1.close();
fr.close();
}
catch(Exception e)
{
System.out.println(e);
}

R How to convert vectors of number with different length into vectors of binary with fixed length
By : Arroba
Date : March 29 2020, 07:55 AM
Does that help I'm not sure what your original numbers are stored as, but here's a solution assuming it's a list of vectors: code :
nums <list(
c(1,2,5,6,9),
c(1,2),
c(3,11)
)
maxn < max(unlist(nums))
lapply(nums, function(x) {
binary < numeric(maxn)
binary[x] < 1
binary
})

Is LSH about transforming vectors to binary vectors for hamming distance?
By : Ajay Acharya
Date : March 29 2020, 07:55 AM

Calculate how many binary numbers with X number of 1 bits exist between two given binary numbers with the same property
By : imokpa
Date : March 29 2020, 07:55 AM
around this issue Don't know if you've got an answer on https://math.stackexchange.com/, but let me take a stab at it. In all the discussions below, we're only interested in numbers with X 1bits. I'm not gonna keep saying that, to keep it simpler. code :
count(X, Y) = Y! / ((YX)! * X!)
smaller(A) = count(1, 2) + count(2, 4) + count(3, 7)

Python program: a tool to convert binary numbers to decimal, and decimal numbers to binary, and a simple textonly menu
By : Raju
Date : March 29 2020, 07:55 AM
may help you . Well, there you go :P Decided to use a switch object because it was interesting. However i'm finding it tough to exit the switch with input '5' code :
class switch(object):
value = None
def __new__(class_, value):
class_.value = value
return True
def case(*args):
return any((arg == switch.value for arg in args))
def bintodec(binnum):
return int(str(binnum), 2)
def add(first, second):
try:
first = int(first,2)
second = int(second,2)
except:
pass
print('result')
print(int(first) + int(second))
print('')
def sub(first, second):
try:
first = int(first,2)
second = int(second,2)
except:
pass
print('result')
print(int(second)  int(first))
print('')
def show_menu():
while True:
print ("What do you want to do?")
print ("1. Enter the first number")
print ("2. Enter the second number")
print ("3. Add the two numbers together")
print ("4. Subtract the second number from the first")
print ("5. Exit the program\n")
ask_for_input = input('Enter Switch\n')
ask_for_input = int(ask_for_input)
while switch(ask_for_input):
if case(1):
ask_for_1_num = input("Enter the first number\n")
break
if case(2):
ask_for_2_num = input("Enter the second number\n")
break
if case(3):
add(ask_for_1_num, ask_for_2_num)
break
if case(4):
sub(ask_for_1_num, ask_for_2_num)
break
if case(5):
break
break
def main():
show_menu()
if __name__ == '__main__':
main()



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