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Binary numbers instead of one hot vectors


Binary numbers instead of one hot vectors

By : Kidson Fung
Date : November 20 2020, 11:01 PM
wish help you to fix your issue It is fine if you encode with binary. But you probably need to add another layer (or a filter) depending on your task and model. Because your encoding now implicates invalid shared features due to the binary representation.
For example, a binary encoding for input (x = [x1, x2]):
code :
'apple' = [0, 0]
'orange' = [0, 1]
'table' = [1, 0]
'chair' = [1, 1]
'fruit' = 0
'furniture' = 1
(argmin W) Loss = y - (w1 * x1 + w2 * x2 + b)
(argmin U,W) Loss = y - (u1 * (w1 * x1 + w2 * x2 + b) +
                         u2 * (w1 * x1 + w2 * x2 + b) +
                         b2)


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Why program not returning binary numbers in Text.txt as it's copying binary numbers from Image.jpeg

Why program not returning binary numbers in Text.txt as it's copying binary numbers from Image.jpeg


By : humdrum75
Date : March 29 2020, 07:55 AM
help you fix your problem Well, it could be because you are reading data from "Image.jpeg" and not "Desert.jpeg". It could also be that you are writing to "Text.txt" and not "text.txt". I could also be that you are copying the jpeg image data byte for byte, and that will be interpreted as text by your text editing program, rather than as 'binary' as you suggest.
What I really want to know is, what did you expect to see in the text file?
code :
try
{
    FileInputStream fr=new FileInputStream("Image.jpeg");
    FileOutputStream fr1=new FileOutputStream("Text.txt");
    PrintWriter out = new PrintWriter(fr1);
    int temp=0;
    while((temp=fr.read())!=-1)
    {                       
        out.write(Integer.toBinaryString(temp) + " ");
    }
    out.close();
    fr1.close();
    fr.close();
}
catch(Exception e)
{
    System.out.println(e);
}
R How to convert vectors of number with different length into vectors of binary with fixed length

R How to convert vectors of number with different length into vectors of binary with fixed length


By : Arroba
Date : March 29 2020, 07:55 AM
Does that help I'm not sure what your original numbers are stored as, but here's a solution assuming it's a list of vectors:
code :
nums <-list(
  c(1,2,5,6,9),
  c(1,2),
  c(3,11)
)

maxn <- max(unlist(nums))

lapply(nums, function(x) {
  binary <- numeric(maxn)
  binary[x] <- 1
  binary
})
Is LSH about transforming vectors to binary vectors for hamming distance?

Is LSH about transforming vectors to binary vectors for hamming distance?


By : Ajay Acharya
Date : March 29 2020, 07:55 AM
around this issue 1) You can bypass it, but then you will work in D dimensions, not N as you say. where N << D. That means that the algorithm has to adapt to D dimensions as well.
Calculate how many binary numbers with X number of 1 bits exist between two given binary numbers with the same property

Calculate how many binary numbers with X number of 1 bits exist between two given binary numbers with the same property


By : imokpa
Date : March 29 2020, 07:55 AM
around this issue Don't know if you've got an answer on https://math.stackexchange.com/, but let me take a stab at it.
In all the discussions below, we're only interested in numbers with X 1-bits. I'm not gonna keep saying that, to keep it simpler.
code :
count(X, Y) = Y! / ((Y-X)! * X!)
smaller(A) = count(1, 2) + count(2, 4) + count(3, 7)
Python program: a tool to convert binary numbers to decimal, and decimal numbers to binary, and a simple text-only menu

Python program: a tool to convert binary numbers to decimal, and decimal numbers to binary, and a simple text-only menu


By : Raju
Date : March 29 2020, 07:55 AM
may help you . Well, there you go :P Decided to use a switch object because it was interesting. However i'm finding it tough to exit the switch with input '5'
code :
class switch(object):
    value = None
    def __new__(class_, value):
        class_.value = value
        return True

def case(*args):
    return any((arg == switch.value for arg in args))

def bintodec(binnum):
    return int(str(binnum), 2)

def add(first, second):
    try:
        first = int(first,2)
        second = int(second,2)
    except:
        pass
    print('result')
    print(int(first) + int(second))
    print('')

def sub(first, second):
    try:
        first = int(first,2)
        second = int(second,2)
    except:
        pass    
    print('result')
    print(int(second) - int(first))
    print('')


def show_menu():

    while True:
        print ("What do you want to do?")
        print ("1. Enter the first number")
        print ("2. Enter the second number")
        print ("3. Add the two numbers together")
        print ("4. Subtract the second number from the first")
        print ("5. Exit the program\n")            
        ask_for_input = input('Enter Switch\n')
        ask_for_input = int(ask_for_input)

        while switch(ask_for_input):
            if case(1):
                ask_for_1_num = input("Enter the first number\n")
                break
            if case(2):
                ask_for_2_num = input("Enter the second number\n")
                break
            if case(3):
                add(ask_for_1_num, ask_for_2_num)
                break
            if case(4):
                sub(ask_for_1_num, ask_for_2_num)
                break
            if case(5):
                break
            break    

def main():
    show_menu()

if __name__ == '__main__':
    main()        
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