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How to return a function that needs 2 parameters with 1


How to return a function that needs 2 parameters with 1

By : nick plam
Date : November 20 2020, 11:01 PM
Any of those help I believe I have solved this problem but having an issue only passing 1 parameter to my final function to return result. Here is the question , You could use this definition of createIterator:
code :
function createIterator(func, n) {
    return function (arg) {
        for (var i = 0; i < n; i++) arg = func(arg);
        return arg;
    };
}

function getDouble(num){
    return num * 2;
}

var doubleIterator = createIterator(getDouble, 2);

console.log(doubleIterator(3)); // => 12
function createIterator(func, n) {
    return [].reduce.bind([...Array(n)], arg => func(arg));
}

function getDouble(num){
    return num * 2;
}

var doubleIterator = createIterator(getDouble, 2);

console.log(doubleIterator(3)); // => 12


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Is it possible for a decorator to return a function with the same parameters as the wrapped function?

Is it possible for a decorator to return a function with the same parameters as the wrapped function?


By : Vivek Chaturvedi
Date : March 29 2020, 07:55 AM
will help you Why make hashable a decorator? Why not just make it a function you can invoke that will raise an exception normally, and then just invoke it in the function body, passing it the thing you want to check?
In fact, judging from how you wrote the decorator, isn't hash() already exactly that? Why not, instead of this:
code :
@hashable
def push(self, item):
    '''
    Push the value item onto the heap, maintaining the heap invariant.
    '''
    return heapq.heappush(self.heap, item)
def push(self, item):
    '''
    Push the value item onto the heap, maintaining the heap invariant.
    '''
    hash(item)
    return heapq.heappush(self.heap, item)
def __setitem__(self, i, y):
    hash(i), hash(y)
    self.heap[self.heap.index(i)] = y
    heapq.heapify(self.heap)
C++ what happens first - destruction of function's parameters or handling of function's return values?

C++ what happens first - destruction of function's parameters or handling of function's return values?


By : Bianca Chan
Date : March 29 2020, 07:55 AM
I hope this helps . I have the following code: , With this signature:
code :
int foo(thing x) {
    return 5;
}
newThing = foo(bar);
Trying to make a function return me another function which returns a sum of two parameters

Trying to make a function return me another function which returns a sum of two parameters


By : user2339222
Date : March 29 2020, 07:55 AM
With these it helps Well, it's OK, you just have a syntax error, a parenthesis that should not be here :
code :
return countApples(a, b)/2;
Call same function multiple times with different parameters. When done: Use each return value in other function

Call same function multiple times with different parameters. When done: Use each return value in other function


By : Joern
Date : March 29 2020, 07:55 AM
will help you The functions as they stand are not currently promises. They do, however, follow the async pattern in node.
You can either use something like promisify-node or do it yourself:
code :
// define the first 2 promises by calling firstFunc with inputs
var promise1 = new Promise(function resolver(resolve, reject) {
    firstFunc(input1, function(err, res){
        if(err) reject(err);
        resolve(res);
    });

var promise2 = new Promise(function resolver(resolve, reject) {
    firstFunc(input2, function(err, res){
        if(err) reject(err);
        resolve(res);
    });

// When promise1 & 2 resolve, execute the then handler
Promise.all([promise1, promise2]).then(function (arr) {
    // Grab the resolved values
    var arr1 = arr[0];
    var arr2 = arr[1];

    // return a new promise that is resolved when middleFunc completes
    return new Promise(function resolver(resolve, reject) {
        middleFunc(arr1, arr2, function(err, res){
            if(err) reject(err);
            resolve(res);
        });
    });
}).then(function (arr3) { // Execute this when middleFunc completes
     return lastFuntion(arr3); // This function looks synchronous
}).catch(function (err) {
    // Handle any errors along the way
});
// Helper function to construct a promise by calling firstFunc with input
var firstFuncHelper = function (input) {
    return new Promise(function resolver(resolve, reject) {
        firstFunc(input, function(err, res){
            if(err) reject(err);
            resolve(res);
        });
};

var promise1 = firstFuncHelper(input1);
var promise2 = firstFuncHelper(input2);

// Rest of code above remains
Make Scheme function for 3 parameters return function for the 3d

Make Scheme function for 3 parameters return function for the 3d


By : Jeffrey Klein
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , You have to return a new function that receives the list. I took the liberty of fixing the indentation and the base case (that's not how you should ask if a list if empty!); pay special attention to the way the recursion is called now:
code :
(define (operList op i)
  (lambda (lis)
    (if (null? lis)
        '()
        (cons (op i (car lis))
              ((operList op i) (cdr lis))))))
((operList + 2) '(1 1 1))
=> '(3 3 3)
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