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Converting code using array to a code using Stacks/Queue


Converting code using array to a code using Stacks/Queue

By : Turn Bull
Date : November 21 2020, 11:01 PM
this will help I hope I understood you right. You fill the first stack s1 with all elements of A and iterate by popping them off. In this loop, create s2 as a copy of s1 and also iterate through its elements by popping off the first element. You can then compare both elements. In Python-like pseudocode, it would look similar to
code :
s1 = A.toStack # It's pseudocode :-)

while !s1.isEmpty():
    elem1 = s1.pop()
    s2 = s1.copy()

    while !s2.isEmpty():
        elem2 = s2.pop()
        if elem1 % elem2 == x:
            return elem1 == elem2


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Implementing 3 stacks using 1 array, will this code work?

Implementing 3 stacks using 1 array, will this code work?


By : Vivek Kumar
Date : March 29 2020, 07:55 AM
like below fixes the issue As far as I can tell, you are correct--it is not storing enough info to indicate holes in memory.
One of the big advantages to a stack is that it can be allocated on top of an array-list instead of a Linked List saving the memory of the previous/next pointers--this implementation eliminates that advantage--it's difficult to imagine an application where this was actually a good solution.
Converting RxJS v4 code to v5, processing a queue with a "pull"

Converting RxJS v4 code to v5, processing a queue with a "pull"


By : David Coy
Date : March 29 2020, 07:55 AM
will help you
flatMap/mergeMap - Now takes a concurrency parameter
Code is not working. Using Stacks

Code is not working. Using Stacks


By : Rogi313
Date : March 29 2020, 07:55 AM
help you fix your problem Here's my code for checking balanced parenthesis which takes an expression and checks if user entered the expression correctly but it isn't working. It gives an error. I don't think so there is an error in the public thing. Please Help! , Your implementation of
code :
void check(string exp)
void dynamicStack::check(string exp) {
...
}
How to check if a queue is empty when I need to use two stacks to form a queue?

How to check if a queue is empty when I need to use two stacks to form a queue?


By : user2731421
Date : March 29 2020, 07:55 AM
should help you out While the purpose of the exercise is very dubious (a convoluted way to abuse the data structures) your have to remember the difference between the stack and the queue. A queue is a first in first out structure, while the stack is first on last out.
If you pop all items from one stack and push them in another you are doing a double inversion. And they FILO stacks can produce FIFO behavior like a queue. But...
code :
def _move_stack(self):
     while not self.in_stack.is_empty():
def dequeue(self):

    If out_stack.is_empty():
        self._move_stack()


    return self.out_stack.pop()
How to continuously feed items from array into two stacks, the two stacks will then feed data into queue

How to continuously feed items from array into two stacks, the two stacks will then feed data into queue


By : user3258546
Date : March 29 2020, 07:55 AM
will be helpful for those in need As I understand the question:
You feed elements into two stacks that have maximum capacity of 7 any items that do not feed into the stacks they go into the queue.
code :
for each item in cargo:
  can I put it in the first stack?
  else can I put in the second stack?
  else put in the queue.
if (lift1.size() < MAX_SIZE) {
   lift1.push(cargo[k]);
else if (lift2.size() < MAX_SIZE) {
  ....
class Lift {
 int capacity;
 boolean emptying;
 Stack<String> stack = new Stack<>();

 public Lift(int maxCapacity) {
  this.capacity = maxCapacity;
  this.emptying = false;
 }


 public boolean push(String item) {
  if (!emptying && stack.size() < capacity) {
    stack.push(item);
    return true;
  } else {
     //state is emptying
     emptying = true;
     return false
  }
 }

 public void pushtoQueue(Queue queue) {
   while(!stack.isEmpty()) {
     queue.add(stack.pop();
   }
   emptying = false;
 }

}
boolean result1 = lift1.push(cargo[k]);
if (!result1) {
  lift2.push(cargo[k]);
} 

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