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Sorting racers / players by places


Sorting racers / players by places

By : Tom
Date : November 21 2020, 11:01 PM
Hope this helps It would be a quite nice to make some preparations before custom sorting. So we avoid a nested sorts in lambda function:
code :
foreach ($racers as $index => $racer) {
    $racers[$index]['sorted_places'] = $racer['places'];
    sort($racers[$index]['sorted_places']);
}
usort($racers, function ($a, $b) {
    unset($value);
    do {
        $topA = array_shift($a['sorted_places']);
        $topB = array_shift($b['sorted_places']);

        if (is_null($topA) && is_null($topB)) {
            $value = 0;
        } elseif (is_null($topA)) {
            $value = 1;
        } elseif (is_null($topB)) {
            $value = -1;
        } elseif ($topA > $topB) {
            $value = 1;
        } elseif ($topA < $topB) {
            $value = -1;
        }
    } while (!isset($value));
    return $value;
});


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Sorting Decimals in mysql to 2 decimal places vs more decimal places

Sorting Decimals in mysql to 2 decimal places vs more decimal places


By : user3349623
Date : March 29 2020, 07:55 AM
hope this fix your issue Store it as integers....This would mean that you would have a smaller index for the overlapping numbers as the percentages would go upto 100% and that would mean that lookups would be faster. Decimals are like storing long intergers in binary form.
Sorting Racers in timing application

Sorting Racers in timing application


By : Muhammad Ali
Date : March 29 2020, 07:55 AM
I wish this helpful for you I'm assuming from your comment to the question, that you have decomposed the problem into sorting and comparing, and that you have got the sorting part covered. Which leaves order comparison.
You need a function that will perform a lexicographic order comparison based first on the number of laps completed, and secondly on the time since the start of this lap. Basically it will look like this:
code :
function CompareRacers(const Left, Right: TTimingRecord): Integer;
begin
  Result := CompareValue(Left.laps, Right.laps);
  if Result=0 then
    Result := CompareDateTime(Left.lastRTCTime, Right.lastRTCTime);
end;
Result := -CompareDateTime(Left.lastRTCTime, Right.lastRTCTime);
Display players in order relative to a user's position in players array

Display players in order relative to a user's position in players array


By : user2972265
Date : March 29 2020, 07:55 AM
around this issue I wanted to do this in line, but it turns out easier to do the logic in the javascript. In a section that processes the game data at a point where I find the user's position (x) in the players array, I put this:
code :
$scope.otherPlayers = $scope.game.players.slice(x).concat( $scope.game.players.slice(0,x) );
.col-md-2(ng-if='player.id != p.id ', ng-repeat='p in otherPlayers')
Try to make a function that will identify players and add two players' cards to left or right side

Try to make a function that will identify players and add two players' cards to left or right side


By : darkben
Date : March 29 2020, 07:55 AM
I wish this help you table.place(player1,card) Should be changed to table.place('player1','Ace of Hearts'). Player 1 should be a string according to your place function.
Selecting unique players' scores from two columns with bubble sorting

Selecting unique players' scores from two columns with bubble sorting


By : Have a question
Date : March 29 2020, 07:55 AM
this one helps. One way to do this is using two nested IN expressions. The inner expression finds all combinations of email and duration that have the lowest duration for that email. The outer expression then finds the email, duration and moves values that are the lowest moves value for that duration (which is the lowest for that email).
code :
SELECT *
FROM scores
WHERE (email, duration, moves) IN (
    SELECT email, duration, MIN(moves)
    FROM scores
    WHERE (email, duration) IN (
        SELECT email, MIN(duration)
        FROM scores
        GROUP BY email)
    GROUP BY email, duration)
ORDER BY duration, moves
id      email           name        duration    moves   submitted
219     foo@bar.com     foo bar     20          36      2019-12-09T20:36:19Z
224     baz@biz.com     baz biz     30          31      2019-12-09T20:36:19Z
233     cow@guy.com     cow guy     31          35      2019-12-09T20:36:19Z
SELECT email, name, duration, MIN(moves) AS moves
FROM scores
WHERE (email, duration) IN (
    SELECT email, MIN(duration)
    FROM scores
    GROUP BY email)
GROUP BY email, name, duration
ORDER BY duration, moves
email           name        duration    moves
foo@bar.com     foo bar     20          36
baz@biz.com     baz biz     30          31
cow@guy.com     cow guy     31          35
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