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How to replace data in a certain node in a linked list?


How to replace data in a certain node in a linked list?

By : Roger Ho
Date : November 21 2020, 11:01 PM
Does that help You mentioned "replace" in your question, so just taking a guess but might be you are expected to replace the node itself and not just the data. In which case, it will be something like this
code :
if(curr_node->data == to_replace_data){
  curr_node->next = new_node;
  new_node->next = curr_node->next->next;
  free( curr_node->next); //or return curr_node->next depending on what
                      // you are trying to do.
}


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Delete the last node of a linked list. Each node has a data pointer as well that points to some data

Delete the last node of a linked list. Each node has a data pointer as well that points to some data


By : user2865323
Date : March 29 2020, 07:55 AM
Any of those help It should ideally read: Node has a "Next" pointer and the node-data itself is a pointer. Such kind of data structures are common where data itself can be huge and cannot be kept in-memory or within the same node.
Edit:
Replace node value in a linked list

Replace node value in a linked list


By : MSadraii
Date : March 29 2020, 07:55 AM
around this issue You need to be testing the strings equality with strcmp, as seen below. In your code, you're testing if two pointers are equal [related post].
code :
#include <string.h>

if(strcmp(s->name, name) == 0) { // if both strings are equal
    s->value = b;
}
while(s != NULL) {
    ...
}
Converting singly linked list to circular linked list by pointing last node to middle node

Converting singly linked list to circular linked list by pointing last node to middle node


By : Quyen Nguyen
Date : March 29 2020, 07:55 AM
hope this fix your issue The only way you would be able to get this to work would be to change:
code :
currentNode = middleNode
currentNode.Next = middleNode
Replace Node in Linked List

Replace Node in Linked List


By : Kriti
Date : March 29 2020, 07:55 AM
hop of those help? I have a function that needs to replace a node of a specified value in the list (old), and replace that node with a new value specified by the user (new). This is what I've come up with, but it makes my program stop working so something's wrong with what I've conjured up. , position of the L = L->next; should be in the loop
code :
 node *modifyNode(node *L, int old, int new)
 {
     while (L != NULL)
     {
       if(L->val == old)
        {
          L->val = new;

        }
      L = L->next; // this should be position to refer next node in the loop
}

}
linked list : how to delete last node, where we have pointer to last node in a single linked list

linked list : how to delete last node, where we have pointer to last node in a single linked list


By : Gonzalo Avaria
Date : March 29 2020, 07:55 AM
it fixes the issue This is generally not possible. You need the address of the node before the last node. This node should have it's next pointer set to NULL. The node before last cannot be directly accessed from the last node in a singly linked list.
However, if you have access to the head node, you can traverse the list again to get the node before the last node.
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