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SQL Concatenation Query - Four As in Concatenated Name


SQL Concatenation Query - Four As in Concatenated Name

By : Sebas Yii
Date : November 21 2020, 11:01 PM
it helps some times I am trying to create a view in SQL. We will call this view "A7T8". The view will pull first and last names from the database, and concatenate the first and last names into a field called FullName. However, I only want to select the concatenated names that have a total of at least four As in their first and last names. (Rebecca Aaronson would not be displayed since she only has 3 As, but Harry Flanagan would be displayed. , You can simply write:
code :
CREATE VIEW A7T8 AS
SELECT FNAME || ' ' || LNAME AS FULLNAME
FROM A7
WHERE UPPER(FNAME || ' ' || LNAME) LIKE '%A%A%A%A%'
ORDER BY LNAME, FNAME;


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Doing two SELECT query, with the second query dependant of the first, and the result of the second being concatenated in

Doing two SELECT query, with the second query dependant of the first, and the result of the second being concatenated in


By : Tracy Blair
Date : March 29 2020, 07:55 AM
I wish this help you Check out the GROUP_CONCAT function
An example usage would be:
code :
SELECT tGathering.*, GROUP_CONCAT(people.cPeople SEPARATOR ',') FROM tGathering
INNER JOIN tGatheredPeople AS people ON `people`.cGatheringID=`tGathering`.cId
GROUP BY people.cGatheringID
Javascript Error - Unterminated String Literal on concatenation if concatenated string has a space in it

Javascript Error - Unterminated String Literal on concatenation if concatenated string has a space in it


By : user3779833
Date : March 29 2020, 07:55 AM
around this issue Your problem isn't spaces, its line breaks in the middle of strings. You can get around that with \ but as Alex K mentioned, that is non standard.
For what its worth, I'd do something like this.
code :
document.getElementById('theID').innerHTML += [ 
"<ul>",
  "<li><a href='", varLink, "'>", var1, "</a></li>",
"</ul>"
].join('');
numpy array concatenation error: 0-d arrays can't be concatenated

numpy array concatenation error: 0-d arrays can't be concatenated


By : Juan Gil
Date : March 29 2020, 07:55 AM
will help you You need to put the arrays you want to concatenate into a sequence (usually a tuple or list) in the argument.
code :
tmp = np.concatenate((allValues, np.array([30], float)))
tmp = np.concatenate([allValues, np.array([30], float)])
a = np.array([1, 2])
b = np.array([3, 4])
np.concatenate(a, b)

# TypeError: only length-1 arrays can be converted to Python scalars
NumPy: Error While Concatenation - zero-dimensional arrays cannot be concatenated

NumPy: Error While Concatenation - zero-dimensional arrays cannot be concatenated


By : Zigarlos
Date : March 29 2020, 07:55 AM
I wish this helpful for you I am trying to concat two valid array via np.concat() method. , Applying np.concatenate to scipy sparse matrices produces this error:
code :
In [162]: from scipy import sparse
In [163]: x=sparse.eye(3)
In [164]: x
Out[164]: 
<3x3 sparse matrix of type '<class 'numpy.float64'>'
    with 3 stored elements (1 diagonals) in DIAgonal format>
In [165]: np.concatenate((x,x))
---------------------------------------------------------------------------
ValueError                                Traceback (most recent call last)
<ipython-input-165-0b67d0029ca6> in <module>()
----> 1 np.concatenate((x,x))

ValueError: zero-dimensional arrays cannot be concatenated
In [168]: sparse.hstack((x,x)).A
Out[168]: 
array([[ 1.,  0.,  0.,  1.,  0.,  0.],
       [ 0.,  1.,  0.,  0.,  1.,  0.],
       [ 0.,  0.,  1.,  0.,  0.,  1.]])
In [169]: sparse.vstack((x,x)).A
Out[169]: 
array([[ 1.,  0.,  0.],
       [ 0.,  1.,  0.],
       [ 0.,  0.,  1.],
       [ 1.,  0.,  0.],
       [ 0.,  1.,  0.],
       [ 0.,  0.,  1.]])
Highlight duplicates of concatenated value WITHOUT creating concatenated values in work sheet

Highlight duplicates of concatenated value WITHOUT creating concatenated values in work sheet


By : user2519550
Date : March 29 2020, 07:55 AM
I think the issue was by ths following , Goal: I have a list of first name last name and want to highlight duplicates when entering a new person. (or click the button to check if its a duplicated) , Why not use conditional formatting with the following formula:
code :
=COUNTIFS($E:$E,$E1,$F:$F,$F1)>1
=COUNTIFS($E$1:$E1,$E1,$F$1:$F1,$F1)>1
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