Why does PHP not find the variable I'm referring to in this small code?
By : lsvife
Date : March 29 2020, 07:55 AM
I wish this helpful for you Why do I get 'undefined variable $image_src' with this code: , Change it to: code :
${'image_src' . $i} = $image_id . '_' . $i;
$var = 'image_src' . $i;
$$var = $image_id . '_' . $i;
$image_src = array();
for ($i=1; $i<=2; $i++) {
$image_src[$i] = $image_id . '_' . $i;
}
echo $image_src[1];
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Passing a CMake variable to C++ source code
By : Darryls316
Date : March 29 2020, 07:55 AM
this will help You can use the configure_file(filename output_file) command. It replaces something like ${VARIABLE} or @VARIABLE@ in file filename with the actual value of cmake variable VARIABLE and writes the result to output_file. So, you can write something like code :
// in C++ code
std::string my_var = "@MY_VAR@";
# in CMakeLists.txt
configure_file(filename.h.in filename.h)
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What is the pCrawl variable referring to in Trie code?
By : Henly Christen
Date : March 29 2020, 07:55 AM
seems to work fine Usually, in C language, a lower case p as a variable name prefix can be interpreted for pointer. This is the case in the example you provided. This is in no case an explicit rule, just a naming convention followed here and there.
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Optimising python code by not referring the variable which refers to other variable and so on
By : BTEndres
Date : March 29 2020, 07:55 AM
Any of those help Well you are supposed to propose a trimed out version of your problem to build a minimal example. Here your code is close to minimal but unfortunately unrelated to the described problem. What matter when it comes to memory are objects and not variables. In Python a variable is no more that a name that referes to an underlying object. Simply an object ends its lifetime and can be garbage collected to free memory as soon as it is no longer reachable, meaning as soon as no variable can access it directly or indirectly. code :
a = "foo and bar" # ok a addresses the string
b = a # b addresses the same string (one single copy)
a += "s" # oops...
a = [1, 2, 3, 4] # ok a point to the list
b = a # b addresses the same list
a.append(5) # oops...
for i in range(2, 11):
dg = df * i
... # process dg
dfs = [df * i for i in range(2, 11)]
for dg in dfs:
... # process dg
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Android error when referring to XML variable in Java code
By : user4008777
Date : March 29 2020, 07:55 AM
this one helps. You should call setContentView before you call findViewById. Otherwise, since the XML won't have been loaded when you call findViewById, there is no way it can find the id.
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