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Code seems to continue running after return statement (in C)


Code seems to continue running after return statement (in C)

By : DanCousins
Date : October 18 2020, 03:08 PM
wish helps you I am trying to create a binary search algorithm and have used two sets of if statements for when the sample is even/uneven. The uneven side currently works as planned and returns true, the even side returns true but then goes to the "catch all" piece of code at the bottom of the function and returns false: , Your code looks like this:
code :
search(...)
{ 
    if(cond)
        return false
    if(cond)
        return true
    else
        search(...)
    return false
}
search(...)
{ 
    if(cond)
        return false
    if(cond)
        return true
    else
        return search(...)
}


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Should I use return/continue statement instead of if-else?

Should I use return/continue statement instead of if-else?


By : user8491
Date : March 29 2020, 07:55 AM
wish of those help The compiler will almost certainly generate the same code. Even if it didn't, the difference will be probably irrelevant. Hence, the relevant argument is certainly how people would read it.
Therefore the question is how similar "//do some stuff" and "do other stuff" are. If they are conceptually similar, use if/else. If they're conceptually different, use continue/return.
Can a function continue after a return statement?

Can a function continue after a return statement?


By : 不折腾不会死
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further No. But yes. No line of the function will be executed after the return statement. However, the return statement also marks the end of the function and therefor the end of the scope. So if you manage to have an object on the stack (like a local variable), it's destructor will be called.
But that's not what you want. You don't want to free what you return, not even after the return statement.
Return code in an if statement is not running, but if I change it to the return variable, it is running. (Vanilla Javasc

Return code in an if statement is not running, but if I change it to the return variable, it is running. (Vanilla Javasc


By : Артем Черкасов
Date : March 29 2020, 07:55 AM
hop of those help? forEach ignores whatever you return to it - returning from it doesn't break out of the forEach and return from the outer function, it simply stops the current iteration and goes onto the next iteration.
You might use .find instead:
code :
var getFireableLaser = function() {
  return lasers.find(aLaser => aLaser.y <= -120);
}
Angular- Typescript code running through loop even after reaching return statement

Angular- Typescript code running through loop even after reaching return statement


By : James Rougeau
Date : March 29 2020, 07:55 AM
hop of those help? I am learning Angular and I ran into a problem today. I am displaying an array of JS objects and when I click on a single item, I want a new component to display only the details of that object. I am using a service to hold and do CRUD operations in the array. Below is the code for getServer which finds a single object in the array by id. , getServer method is called by 2 things as commented
code :
ngOnInit() {
  const id = +this.activatedRoute.snapshot.params["id"];
  this.server = this.serversService.getServer(id); // Here with id as number
  this.activatedRoute.params.subscribe(
    (params:Params)=>{
      this.server = this.serversService.getServer(params["id"]); // Here with id as string
    }
  );
}
getServer(id: number) {
  const server = this.servers.find(
    (s) => {
      return s.id === id;
    }
  );
  return server;
}
Does continue prevent the else block from running in a for/else statement?

Does continue prevent the else block from running in a for/else statement?


By : Sar Sou
Date : October 02 2020, 12:00 AM
Hope this helps continue does not affect the else: clause. The else clause is run if the loop terminated normally, that is, if a StopIteration is (implicitly) raised by the iterator.
The continue statement does nothing for the particular iteration, however it does not prevent the iterator from being exhausted.
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