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PHP Get a specific property from an array of objects with different array count


By : puti lalaki
Date : October 18 2020, 03:08 PM
Does that help I am in a confusing situation right now. , use nested foreach loop e.g:
code :
foreach($main as $m){
   foreach($m as $item){
     echo $item->ID ." ".$item->Name;
   }
}


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Count number of items in an array of objects with a specific property value (JavaScript)


By : user3780599
Date : March 29 2020, 07:55 AM
will be helpful for those in need D3 would cope with either result format - it does slightly depend on what you want to do with it. Regardless, here is some example code for generating either format:
code :
var result = {};
array.forEach(function(i) {
    if (!result.hasOwnProperty(i.created)) {
        result[i.created] = 0;
    }
    if (i.status === 1) {
        result[i.created] += 1;
    }
});

var newArrayA = Object.keys(result)
                      .map(function(k) {
                          var o={};
                          o[k] = result[k];
                          return o;
                      })

var newArrayB = Object.keys(result)
                      .map(function(k) { return [k,result[k]] })

Count elements that have the same value for a specific property and put the result in an array of objects


By : toufik1511
Date : March 29 2020, 07:55 AM
With these it helps Using Array.reduce, I am trying to count the elements that have the same value for a specific property. I want to put the result in an array of objects containing a property for the value of the grouped by property and another one for the count. How can I do this easily in javascript ? , You already got the what you want just transform it into an array
code :
const CATEGORY = {
  STRATEGY: 'STRATEGY',
  CONTENT: 'CONTENT',
  ADVERTISING: 'ADVERTISING',
  MEASURMENT: 'MEASURMENT'
}

const lessons = [{
  title: 'ohoho',
  category: CATEGORY.STRATEGY
}, {
  title: 'hihihi',
  category: CATEGORY.CONTENT
}, {
  title: 'hello',
  category: CATEGORY.CONTENT
}]

let count = lessons.reduce(function(acc, lesson) {
  acc[lesson.category] ? acc[lesson.category] ++ : acc[lesson.category] = 1
  return acc
}, {})

// transform count into what you want
let categoryLessonCount = [];
for (let cat in count) {
  categoryLessonCount.push({
    'title': cat,
    'count': count[cat]
  });
}

console.log(categoryLessonCount)

Objects with no '.Count' Property - use of @() (array subexpression operator) vs. [Array] cast


By : Qian Chen
Date : March 29 2020, 07:55 AM
I wish this help you In PSv3+, with its unified handling of scalars and collections, any object - even $null - should have a .Count property (and, with the exception of $null, should support indexing with [0]).
Any occurrence of an object not supporting the above should be considered a bug.

ngFor to iterate an array of objects and count the length of an array property


By : user2435961
Date : March 29 2020, 07:55 AM
will help you You iterate over competitions array but try to get competition.sessions[i]. You need something like this:
code :
<ng-container *ngFor="let competition of competitions; index as i">
   <h3>{{competition.name}}</h3>
   <div *ngFor="let session of competition.sessions">
      {{session.program.length}}
      {{session.events.length}}
   </div>
</ng-container>
this.competitionResults = this.competitions
   .map(competition => competition.sessions
       .reduce((res, session) => 
           ({
                programLength: res.programLength + session.program.length, 
                eventLength: res.eventLength + session.events.length,
           }), {
                programLength: 0, 
                eventLength: 0,
           }))
   )
<ng-container *ngFor="let competitionResult of competitionResults">
   {{ competitionResult.programLength }}
   {{ competitionResult.eventLength}}
</ng-container>

Remove duplicates from array, convert to array of objects and add duplicate count property


By : Insankesepian
Date : March 29 2020, 07:55 AM
To fix the issue you can do Ecmascript5 solution using Array.prototype.reduce() function:
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