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What am I supposed to write in my if condition in order to check if there is a record in my MySQL query?


What am I supposed to write in my if condition in order to check if there is a record in my MySQL query?

By : lauraspeck
Date : October 18 2020, 03:08 PM
wish helps you What am I supposed to write in my if condition in order to check if there is a record in my MySQL query? I want to console.log('Taken') if there is already a user with the post-ed username in my user table. , You can check whether the result have items:
code :
db.query('SELECT username FROM user WHERE username = ?', [username], function(err, result) {
    if (err) throw err;
    if (result.length) { // will test if result.lenght is > 0
        console.log('Taken');
    } else {
        console.log('Free')
    }
});


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MySQL update query with where condition only updating one record

MySQL update query with where condition only updating one record


By : user3403074
Date : March 29 2020, 07:55 AM
I wish did fix the issue. Assuming you have a product_id in your product_listings table, which relates to an id field in your product_details table, you can do this:
code :
update products p 
    inner join (
        select product_id, min(price) min_price 
            from product_listing 
            group by product_id
        ) pl 
    on p.id = pl.product_id 
    SET p.min_price = pl.min_price
update products p 
    inner join (
        select product_name, min(price) min_price 
            from product_listing 
            group by product_name
        ) pl 
    on p.product_name = pl.product_name 
    SET p.min_price = pl.min_price
how to add where condition in mysql query before 30 days record

how to add where condition in mysql query before 30 days record


By : Prakash Singh
Date : March 29 2020, 07:55 AM
may help you . I tried to make a query to get the record 30 days before record. I have two table student and student attend tracking. I tried to get who absent for before 30 days. And my query and result. , Try this:
code :
SELECT *
FROM (SELECT std_id, MAX(atr.created) last_attended
        FROM attend_track atr
        GROUP BY std_id) lst
INNER JOIN student st ON st.std_id = lst.std_id
WHERE DATEDIFF(NOW(), DATE(last_attended)) > 30 
Can we write group by to get first record of the order by in Oracle sql? Or can you suggest solution for given query?

Can we write group by to get first record of the order by in Oracle sql? Or can you suggest solution for given query?


By : Yuzakki
Date : March 29 2020, 07:55 AM
I wish this helpful for you This would be easier to interpret with sample data and results, but it sounds like you want something like:
code :
select devid, runtime, status, prev_status,
  coalesce(good_status, prev_status) as best_status
from (
  select devid, runtime, status,
    lag(status) over (partition by devid order by runtime) as prev_status,
    max(case when status = 'Good' then status end) over (partition by devid) as good_status
  from (
    select devid, runtime, status
    from devtable
    where runtime > date '2018-06-30'
  )
)
where runtime = date '2018-07-17';
with devtable (devid, runtime, status) as (
            select 1, date '2018-06-30', 'Good' from dual -- should be ignored
  union all select 1, date '2018-07-01', 'a' from dual
  union all select 1, date '2018-07-16', 'b' from dual
  union all select 1, date '2018-07-17', 'c' from dual
  union all select 2, date '2018-07-01', 'Good' from dual
  union all select 2, date '2018-07-16', 'e' from dual
  union all select 2, date '2018-07-17', 'f' from dual
  union all select 3, date '2018-07-01', 'g' from dual
  union all select 3, date '2018-07-16', 'Good' from dual
  union all select 3, date '2018-07-17', 'i' from dual
  union all select 4, date '2018-07-01', 'j' from dual
  union all select 4, date '2018-07-16', 'k' from dual
  union all select 4, date '2018-07-17', 'Good' from dual
)
select devid, runtime, status, prev_status,
  coalesce(good_status, prev_status) as best_status
from (
  select devid, runtime, status,
    lag(status) over (partition by devid order by runtime) as prev_status,
    max(case when status = 'Good' then status end) over (partition by devid) as good_status
  from (
    select devid, runtime, status
    from devtable
    where runtime > date '2018-06-30'
  )
)
where runtime = date '2018-07-17';

     DEVID RUNTIME    STAT PREV BEST
---------- ---------- ---- ---- ----
         1 2018-07-17 c    b    b   
         2 2018-07-17 f    e    Good
         3 2018-07-17 i    Good Good
         4 2018-07-17 Good k    Good
select devid, runtime, status, prev_status,
  coalesce(good_status, prev_status) as best_status
from (
  select devid, runtime, status,
    lag(status) over (partition by devid order by runtime) as prev_status,
    max(case when runtime > date '2018-06-30' and status = 'Good' then status end)
      over (partition by devid) as good_status
  from devtable
)
where runtime = date '2018-07-17';
How to write sql request through Active Record Query Interface with joins two tables where condition - array of ids

How to write sql request through Active Record Query Interface with joins two tables where condition - array of ids


By : user3220351
Date : March 29 2020, 07:55 AM
this one helps. This is pure ActiveRecord without Rails models, just connection to another mysql db. I tried to write a request like this: , Use IN for multiple values (Array):
code :
Product.joins('inner join oc_product_description on oc_product_description.product_id = oc_product.product_id')
       .where('oc_product.product_id IN (?)',[64,66,70,71])
MySQL fetch record as in order passed for IN condition

MySQL fetch record as in order passed for IN condition


By : Yagnik Gondaliya
Date : March 29 2020, 07:55 AM
wish helps you Want result in same order as passed to IN condition:
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