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Multi Thread Server Multiple Port Send File Same Time


Multi Thread Server Multiple Port Send File Same Time

By : Manuel Babuglia
Date : October 18 2020, 01:08 AM
help you fix your problem I use multiple port and Multi thread Server when I send file from client to server like bellow code or from server to client. But I can't send data in same time for different port. I think I must use paralel programing do you have any suggestion for solution or Can you give me source or internet website suggestion for this topic. , The pattern for multithread servers is something pseudo coded as:
code :
//server side
while (true) {
    accept a connection;
    create a thread to deal with the client;
}
while(this.isRunning) {
    Socket clientSocket = null;
    try {
        clientSocket = this.serverSocket.accept();
    } catch (IOException e) {
        //handle exception on accept client socket
    }
    if(clientSocket != null) {
        Thread workerThread = new Thread(
            new YourWorkerRunnable(clientSocket /*, remain arguments */));
        workerThread.start();  
    } 
}


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How to send file from server to multiple clients at a time in mfc using sockets?

How to send file from server to multiple clients at a time in mfc using sockets?


By : user1844112
Date : March 29 2020, 07:55 AM
I hope this helps . Creating thread for each client will transfer file to each client at a time.
Multi-threaded Server handling multiple clients in one thread

Multi-threaded Server handling multiple clients in one thread


By : sonic
Date : March 29 2020, 07:55 AM
fixed the issue. Will look into that further First off, have a look at using poll() instead of select(): it works better when you have large number of file descriptors used from different threads.
To get threads currently waiting in I/O out of waiting I'm aware of two methods:
If a client Udp port punches to a server on one port, can I assume it will send from same port if it sends to a differen

If a client Udp port punches to a server on one port, can I assume it will send from same port if it sends to a differen


By : user2062697
Date : March 29 2020, 07:55 AM
To fix the issue you can do No you can not assume that. It may happen or it may not happen, it is up to the writers of the software of the NAT firewall the client is punching through.
A complex software may detect that you are talking to the same server but a different port and reuse the outbound port, but simpler software (the kind you would frequently see on home routers) may be "dumber" and just use a new randomized port per connection.
jQuery AJAX multiple files upload but send one file at a time to server using ajax

jQuery AJAX multiple files upload but send one file at a time to server using ajax


By : Leslie Lee
Date : March 29 2020, 07:55 AM
To fix this issue I have following html , You can just use forEach method of FormData:
code :
$('#submit-form').submit(function(e) {
  e.preventDefault();
  var formData = new FormData(this);
  var url = "upload-files.php";

  formData.forEach(function(entry) {
    if (entry instanceof File) {
      var fileForm = new FormData()
      fileForm.append('resume', entry)

      $.ajax({
        url: url,
        type: 'post',
        data: fileForm,
        success: function(response) {
          alert(response);
        },
        cache: false,
        contentType: false,
        processData: false
      })
    }
  })
})
Multiple clients connecting to same server port at the same time?

Multiple clients connecting to same server port at the same time?


By : Suraj
Date : March 29 2020, 07:55 AM
hop of those help? Note: UDP doesn't really have a concept of "connect", just sending and receiving packets. (e.g. if making a TCP connection is analogous to making telephone call, then sending a UDP packet is more like mailing a letter).
Regarding two sockets arriving at the same UDP port on a server at the same time: the TCP/IP stack keeps a fixed-size receive-buffer for each socket that the server creates, and whenever a packet arrives at the port that socket is bound to, the packet is placed into that buffer. Then the server program is woken up and can recv() the data whenever it cares to do so. So in most cases, both packets will be placed into the buffer and then recv()'d and processed by the server program. The exception would be if there is not enough room left in the buffer for one or both of the packets to fit into it (remember it's a fixed-size buffer); in that case, the packet(s) that wouldn't fit into the buffer will simply be dropped and never seen again.
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