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Modification of Bubblesort program with user input


By : Daus Daus
Date : October 17 2020, 03:08 PM
around this issue That's because int[] numbers = new int[] {scan.nextInt()}; is a single assigment. scan read a single input and assign to number[0].
You actually need to modify your code for scan to read n numbers and store in n-sized numbers.
code :
int[] numbers = new int[scan.nextInt()];
for( int i = 0; i < numbers.length; i++)
   numbers[i] = scan.nextInt();


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Excel 2010 VBA User Written Function Modification of Input parameter


By : Gopal Bosu
Date : March 29 2020, 07:55 AM
it helps some times As User defined functions(UDF) cannot change the state of the workbook/worksheet etc.You can use the worksheet change event.
Copy this code to the worksheet where you are entering the function
code :
    Private Sub Worksheet_Change(ByVal Target As Range) 
Application.EnableEvents=False
     if Target.Address = "$A$1" and target.count = 1 Then ' change in first parameter - first parameter
       if Target.Value ="something" then    Range("B1").Value ="change"
         '$A$1 is the location of fist paramenter
         'range("b1") is second parameter on assumption
      end if
   Application.EnableEvents=True
    End Sub 

Perl script: modification to avoid necessity of user input


By : Syshella
Date : March 29 2020, 07:55 AM
Does that help I use the following code to make a pdf file from jpgs. It works fine but what I would like to achieve is to modify this script so that it could be used without any user input. I would like to right click a folder in Windows choose this script and have a pdf made. So this script needs to get a folder name and create a pdf file without asking for its name. It would be perfect if the name of final pdf would be the same as the folder where jps are. Could you help me, please? , You can use the @ARGV array to grab parameters for the command line.
code :
#!/usr/bin/perl

use PDF::API2;
use strict;

# assume all just one directory path
my $folder = join(' ', @ARGV);

# deal with dos paths
$folder =~ s|\\|/|g;

$folder =~ s|/$||;

my $pdf_file = $folder . '.pdf';

die "Not a folder!\n" unless -d $folder;
die "There's already a pdf of that name!\n" if -f $pdf_file;

my $pdf = PDF::API2->new;

opendir DIR, $folder;
while(my $file = readdir DIR) {
    next unless $file =~ /\.je?pg$/i;
    my $jpg = $folder . '/' . $file;

    my $image = $pdf->image_jpeg($jpg);
    my $page = $pdf->page();
    $page->mediabox(0,0,$image->width, $image->height);
    $page->trimbox(0,0,$image->width, $image->height);
    my $gfx = $page->gfx;
    $gfx->image($image, 0, 0);
}
close DIR;

$pdf->saveas($pdf_file);

Please explain the cut in the Bubblesort Prolog program?


By : moussaoui med
Date : March 29 2020, 07:55 AM
will be helpful for those in need There are several possibilities to make the goal swap(List, List1) fail. Either List is a list of length 0 or 1 ; or it does not contain two immediately succeeding elements where the second is smaller than the first.
The cut is placed in such a manner that it both cuts swap/2 and the alternative of bubblesort/2.

Output of program for user input giving different length for consonant with user input. input 1 --> abc input2-->


By : ChrisL22
Date : March 29 2020, 07:55 AM
this one helps. Long answer: So your string is 'abc' which is 5 characters long. python is checking:
if first character ' is in vowels and it is not so consonant = 0+1 second character is a, it is in vowels so vowels = 0+1 third b which is not in vowels, so consonant = 1+1 (which is 2 now) fourth c which is not in vowels, so consonant = 2+1 (which is 3 now) fifth character is ' which is not in vowels, so consonant = 3+1 (which is 4 now)

Can there be more than one program for bubblesort?


By : Jae Park
Date : March 29 2020, 07:55 AM
like below fixes the issue At first glance, yes, barring subtle bugs, both of these are bubble sorts. There's nothing special about which way the bubbling goes; most implementations bubble "up" from left to right, but there is no hard and fast rule that bans bubbling "down" from right to left.
As a general rule, if the question is "Is there more than one way to do it?", in programming, the answer is "Yes".
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