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Use of for loop to delete rows of specific instances in R

By : miguel orellana
Date : October 17 2020, 03:08 PM
wish helps you Could you please let me know know how I could only keep the row with the highest hands for every different players? I intended to do a for loop but I could not figure out how to solve it. , Try this:
code :

df %>%
  group_by(Player) %>%
  filter(Hands == max(Hands))
# A tibble: 3 x 3
# Groups:   Player [3]
  Player `PKMP ID` Hands
   <int>    <fctr> <int>
1   1141   PKMP002 23658
2   1714   PKMP016   678
3   1745   PKMP032  6821

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Delete specific Rows without using Do Until loop

By : chridder
Date : March 29 2020, 07:55 AM
This might help you You can rewrite it to a For loop. This will allow you to cut out a bit of code. I would also recommend adding static variables outside of the loops. This will remove any unnecessary processing. I ran this and it seemed to run quite quickly.
code :
Sub main()

    Dim i As Integer
    Dim ch As String, str As String
    Dim ws1 As Worksheet
    Dim wb1 As Workbook
    Dim last As Long

    Set wb1 = ThisWorkbook
    Set ws1 = wb1.Sheets("Source")
    last = ws1.Cells(Rows.Count, "F").End(xlUp).Row

    str = 314

    Application.ScreenUpdating = False
    Application.Calculation = xlCalculationManual

    For i = last To 2 Step -1
        If Left(ws1.Cells(i, 6), 3) = str Then
            ws1.Cells(i, 6).Rows.EntireRow.Delete
        End If

    Application.ScreenUpdating = True
    Application.Calculation = xlCalculationAutomatic

End Sub

Delete specific rows from selection in for each loop

By : Rabbi Cheeran Benny
Date : March 29 2020, 07:55 AM
should help you out Always run from the bottom to the top when deleting rows or you risk skipping rows (as you have noticed).
code :
'don't dim inside a loop
Dim r As Long
Dim strArray As Variant
Dim intCount As Integer
Dim intWords As Integer

With Selection
    For r = .Rows.Count To 1 Step -1

        strArray = Split(Selection.Cells(r).Value & " ", " ")
        intWords = 0

        For intCount = LBound(strArray) To UBound(strArray) - 1
            If dict.Exists(Trim(strArray(intCount))) Then
                dict(Trim(strArray(intCount))) = dict(Trim(strArray(intCount))) + 1
                dict.Add Key:=Trim(strArray(intCount)), Item:=1
                intWords = intWords + 1
            End If
        Next intCount

        If intWords = 0 Then
        End If

    Next r
End With

VBA Loop: if cell contains specific value then delete the row containing the value and the next 3 rows below

By : FotbalCB
Date : March 29 2020, 07:55 AM
will be helpful for those in need Hi there I am trying to loop through a long report that removes deletions. , I think you just to fix this part and put the colon in the quotes.
code :
If Range("B" & x).Value = "DELETE" Then Range("A" & x & ":I" & x + 4)).ClearContents
If Cells(x,"B").Value = .....
Sub RemoveDel()
lastrow = Cells(Rows.Count, "B").End(xlUp).Row
For x = 1 To lastrow

    If Range("B" & x).Value = "DELETE" Then Range("A" & x & ":I" & x + 4).ClearContents

Next x
End Sub

Delete 2 Rows above if specific cell is blank [Loop]

By : Khamzat
Date : March 29 2020, 07:55 AM
This might help you One way to achieve this would be as follows, the reason I delete the rows below (586) before checking the rows above (505) is because once you delete the row, the rows shift up, in essence changing the row numbers:
code :
Sub foo()
Dim ws As Worksheet: Set ws = Sheets("Sheet1")
    If ws.Range("B586").Value = "" Then ws.Rows("584:585").Delete
    If ws.Range("B505").Value = "" Then ws.Rows("503:504").Delete
End Sub

For Each loop won't delete all rows with specific values

By : Thad Myers
Date : March 29 2020, 07:55 AM
Hope that helps Modifying a collection you're iterating is always a bad idea. Sure you could start at the bottom and call it a day, but then your next question is going to be "my code is painfully slow, how do I make it faster?"
Have a CombineRanges function responsible for Union-ing ranges:
code :
Private Function CombineRanges(ByVal source As Range, ByVal toCombine As Range) As Range
    If source Is Nothing Then
        Set CombineRanges = toCombine
        Set CombineRanges = Union(source, toCombine)
    End If
End Function
Dim toDelete As Range
Dim cell As Range
For Each cell In ActiveSheet.Range("B11:B25")
    If cell.Value <> "Total" Then Set toDelete = CombineRanges(toDelete, cell)

If Not toDelete Is Nothing Then toDelete.EntireRow.Delete
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