logo
Tags down

shadow

Date values from an int and a string in separate columns


By : Carlos Margiotta
Date : October 17 2020, 01:08 AM
it fixes the issue Your best option is to use the dateparse formula. That way you can combine your separate fields and create a new datestamp.
Create the calculated field as follows, note here I have made the day the 1st of the month you could change this to suite your purpose:
code :
dateparse('ddMMMMyyyy', '01'+[Manufacture Month]+str([Manufactured year]))


Share : facebook icon twitter icon

Java, date from separate JSON values to string to date


By : user3279153
Date : March 29 2020, 07:55 AM
this one helps. Assuming that the goal is to transform a String representation of date information, formatted for example as "2011-5-30 16:13:47", into a java.util.Date instance...
code :
String dateString = "2011-5-30 16:13:47";
Date date = new SimpleDateFormat("yyyy-M-dd HH:mm:ss").parse(dateString);
System.out.println(date);
// output: Mon May 30 16:13:47 MST 2011

String dateString2 = "2011-11-3 16:13:47";
Date date2 = new SimpleDateFormat("yyyy-M-dd HH:mm:ss").parse(dateString2);
System.out.println(date2);
// output: Thu Nov 03 16:13:47 MST 2011

Select from table where date and time values are in separate columns


By : sumit78
Date : March 29 2020, 07:55 AM
it should still fix some issue I have a dateColumn with value "2014-10-10" and startTimeColumn with value "10:10:44". How can I select everything from the table where dateColumn is between 'startDate' and 'endDate', and where the startTimeColumn is greater than or equal to 'startTime' on the 'startDate'? , Combine the date and time columns
code :
SELECT * FROM table1 
WHERE timestamp(dateColumn, startTimeColumn) BETWEEN 'startDateAndTime' 
                                                 AND 'endDateAndTime'

sql query to retrieve min to max date and their corresponding values to separate Columns


By : user3575045
Date : March 29 2020, 07:55 AM
help you fix your problem I take it from your comment that an ID may have less than, but never more than three drugs.
In that case, this is one way to get your desired output:
code :
WITH cte AS (
  SELECT [ID], [VALUE], ROW_NUMBER() OVER (Partition By [ID], Order By [Dates] ASC) AS RN
)
SELECT [ID], 
MAX(CASE WHEN RN=1 THEN [VALUE] ELSE NULL END) AS FirstDrug,
MAX(CASE WHEN RN=2 THEN [VALUE] ELSE NULL END) AS SecondDrug,
MAX(CASE WHEN RN=3 THEN [VALUE] ELSE NULL END) AS ThirdDrug
FROM cte
GROUP BY [ID]

MySQL: Max Date(), Summarizing Values of Last Date for Separate Columns


By : Divya
Date : March 29 2020, 07:55 AM
may help you . You need to group by both company_name and wing_name in the subquery, then group the main query by just company_name to combine the rows that were selected.
code :
SELECT t1.company_name, SUM(t1.employees) AS employees, AVG(t1.qa_score) AS qa_score
FROM table AS t1
JOIN (SELECT company_name, wing_name, MAX(date_time) AS maxtime
      FROM table
      GROUP BY company_name, wing_name) AS t2
ON t1.company_name = t2.company_name AND t1.wing_name = t2.wing_name AND t1.date_time = t2.maxtime
GROUP BY t1.company_name

How to do SQLite date comparison if month and year are stored in separate columns as integer values


By : rob
Date : March 29 2020, 07:55 AM
wish of those help If you know the year and month of the given date range, you do not need date functions.
A record is in the range if its year is after the range's start year, or, if both are in the same year, if the record's month is the same or after the range's start month. The comparions for the range end are similar:
Related Posts Related Posts :
shadow
Privacy Policy - Terms - Contact Us © soohba.com