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My regex doesn't match with a certain input - java

By : Maggie De Williams
Date : October 16 2020, 03:08 PM
may help you . Please have a look at your ( ?([0-9]+)-?)+ regex demo: only 4 6 8 2 5-3 4 3 9 line is matched as a whole line while 4 -6 8 2 5-3 4 3 9, -4 6 8 2 5 -3 4 3 9, and 4 -6 8 2 5-3 4 3 9 are matched partially.
If you get false, it means you are using .matches() method. You may use
code :
(?: ?-?([0-9]+))+

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How can i match particular format in input using java.util.regex in java?

By : KissMySite Media
Date : March 29 2020, 07:55 AM
Any of those help INPUT , I would recommend using Matcher.appendReplacement:
code :
public static void main(final String[] args) throws Exception {
    final String[] loginURLs = {
    final Pattern patt = Pattern.compile("(\\?)?&?(TXT\\{[^}]++})(&)?");
    for (final String loginURL : loginURLs) {
        System.out.printf("%1$-10s %2$s%n", "Processing", loginURL);
        final StringBuffer sb = new StringBuffer();
        final Matcher matcher = patt.matcher(loginURL);
        while (matcher.find()) {
            final String found = matcher.group(2);
            System.out.printf("%1$-10s %2$s%n", "Found", found);
            if (matcher.group(1) != null && matcher.group(3) != null) {
                matcher.appendReplacement(sb, "$1");                
            } else {
                matcher.appendReplacement(sb, "$3");
        System.out.printf("%1$-10s %2$s%n%n", "Processed", sb.toString());
Processing http://ip:port/path?username=abcd&location={LOCATION}&TXT{UE-IP,UE-Username,UE-Password}&password={PASS}
Found      TXT{UE-IP,UE-Username,UE-Password}
Processed  http://ip:port/path?username=abcd&location={LOCATION}&password={PASS}

Processing http://ip:port/path?username=abcd&location={LOCATION}&password={PASS}&TXT{UE-IP,UE-Username,UE-Password}
Found      TXT{UE-IP,UE-Username,UE-Password}
Processed  http://ip:port/path?username=abcd&location={LOCATION}&password={PASS}

Processing http://ip:port/path?TXT{UE-IP,UE-Username,UE-Password}&username=abcd&location={LOCATION}&password={PASS}
Found      TXT{UE-IP,UE-Username,UE-Password}
Processed  http://ip:port/path?username=abcd&location={LOCATION}&password={PASS}

Processing http://ip:port/path?TXT{UE-IP,UE-Username,UE-Password}
Found      TXT{UE-IP,UE-Username,UE-Password}
Processed  http://ip:port/path

Processing http://ip:port/path?username=abcd&password={PASS}
Processed  http://ip:port/path?username=abcd&password={PASS}
if (matcher.group(1) != null && matcher.group(3) != null) {
    matcher.appendReplacement(sb, "$1");                
} else {
    matcher.appendReplacement(sb, "$3");

A regex to match string that doesnt start with ... and doesnt end with

By : Galaydh
Date : March 29 2020, 07:55 AM
Any of those help I'm trying to find a Regex that matches a word but doesn't start/end with a specific character. , You can use lookaround based regex in PHP (PCRE):
code :

Java regex matcher doesnt match

By : Ryan Rodrigues
Date : March 29 2020, 07:55 AM
wish help you to fix your issue The escaping character in both regex and java String literals is a backslash, not a forward slash. You want to get \d in regex (escaped d for digits). You have to escape it by another backslash in string literal, so you obtain \\d.
code :
"place (\\d+);(\\d+);(\\d+);(\\d+)"
String pattern = "place (//d+);(//d+);(//d+);(//d+)".replaceAll("//", "\\\\");

Java regex doesnt match outside of ascii range, behaves different than python regex

By : Siddharth Insan
Date : March 29 2020, 07:55 AM
hop of those help? As suggested by Wiktor in the comments, you could use (?U) to turn on the flag UNICODE_CHARACTER_CLASS. While this does allow matching äöa, this still doesn't match m². That's because UNICODE_CHARACTER_CLASS with \w doesn't recognize ² as a valid alphanumeric character. As a replacement for \w, you can use [\pN\pL_]. This matches Unicode numbers \pN and Unicode letters \pL (plus _). The \pN Unicode character class includes the \pNo character class, which includes the Latin 1 Supplement - Latin-1 punctuation and symbols character class (it includes ²³¹). Alternatively, you could just add the \pNo Unicode character class to a character class with \w. This means the following regular expressions correctly match your strings:
code :
[\pN\pL_]{2,}         # Matches any Unicode number or letter, and underscore
(?U)[\w\pNo]{2,}      # Uses UNICODE_CHARACTER_CLASS so that \w matches Unicode.
                      # Adds \pNo to additionally match ²³¹
int _PyUnicode_IsDecimalDigit(Py_UCS4 ch)
    if (_PyUnicode_ToDecimalDigit(ch) < 0)
        return 0;
    return 1;
int _PyUnicode_ToDecimalDigit(Py_UCS4 ch)
    const _PyUnicode_TypeRecord *ctype = gettyperecord(ch);

    return (ctype->flags & DECIMAL_MASK) ? ctype->decimal : -1;

Dynamic input text box id doesnt match the regex format. shows undefined

By : Evgeny
Date : March 29 2020, 07:55 AM
To fix this issue You may want to use a better selector for the input elements. You can use input[id^='points'] for example. This will look for input elements with a the id that starts with points.
Consider the following example:
code :
var results = $("input[id^='points']");
var points = 'Enter a valid point.';
var regex = '/^[A-Za-z!@#></!?\$%\^\&*\)\(+=._-]+$/g';
results.each(function(i, el) {
  if ($(el).val().match(regex)) {
    console.log("Match on #" + $(el).attr("id"));
    $("<span>", {
      class: "errTextboxClass"
    }).css("color", "#e03b3b;").html(points).insertAfter($(el));
$(function() {
  $("input[id^='points']").keypress(function(e) {
    if (e.which !== 46 && (e.which < 48 || e.which > 57)) {
label {
  width: 80px;
  display: inline-block;
<script src="https://cdnjs.cloudflare.com/ajax/libs/jquery/3.3.1/jquery.min.js"></script>
  <label>Points 1</label> <input id="points1" type="text">
  <label>Points 2</label> <input id="points2" type="text">
  <label>Name</label> <input id="name1" type="text">
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