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In c++ how do I go about using pointers to get the average of an array?


By : TOGR
Date : October 16 2020, 03:08 PM
I wish this help you First of all your function getAverage() has different prototype than that you defined. And secondly you try to pass std::unique_ptr object into a function that instead expects a int*. But std::unique_ptr is a different type than int* and not implicitly convertible. So to pass int *use std::unique_ptr::get function. like
code :
#include <iostream>
#include <iomanip>
#include <memory>
using namespace std;

double getAverage(int *, int);

int main()
{ 
    int size = 0;
    cout << "How many scores will you enter? ";
cin >> size;

unique_ptr<int[]> ptr(new int[size]);


cout << endl;
int count = 0;

//gets the test scores

for (count = 0; count < size; count++)
{
    cout << "Enter the score for test " << (count + 1) << ": ";
    cin >> ptr[count];
    cout << endl;
}
//display test scores
cout << "The scores you entered are:";
for (count = 0; count < size; count++)
    cout << " " << ptr[count];
cout << endl;

double avg;
avg = getAverage(ptr.get(), size);
cout << setprecision(2) << fixed << showpoint << endl;

cout << "The average is " << avg << endl;

return 0;
}

double getAverage(int *ptr, int size)
{
double average1;
double total = 0;
for (int count = 0; count < size; count++)
{
    total = total + *(ptr + count);
}
average1 = total / size;

return average1;
} 


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Efficient way of calculating average difference of array elements from array average value


By : lucacard87
Date : March 29 2020, 07:55 AM
it helps some times I don't think you can do better than O(n log n).
Suppose the array were sorted. Then we could divide it into the elements less than the average and the elements greater than the average. (If some elements are equal to the average, that doesn't matter.) Suppose the first k elements are less than the average. Then the average distance is

Create an array from MySQL query, average the values of that array, then round that average up


By : Abhishek Sharma
Date : March 29 2020, 07:55 AM
like below fixes the issue Ok. Here is the code I have so far... , Your problem is here:
code :
$userrating = mysql_query($userratingquery) or die('SQL Error :: '.mysql_error());
$userrating = array();

Prompting the user for 10 inputs, sotring it in an array, finding the average, and printing numbers less than average


By : user7802004
Date : March 29 2020, 07:55 AM
this one helps. You're almost there, but you're only prompting once and placing the input in to a variable. You need to prompt 10 times if you want 10 numbers (otherwise you need to parse the input and extract 10 numbers from it).
Assuming you wanted a few methods of populating elmt through ask (here i use input instead of ask and nums instead of elmt--but we're talking minor semantics):
code :
// initialize array with 10 elements
var nums = new Array(10);
// iterate over each element and prompt for value
for (var i = 0; i < nums.length; i++){
  var input = prompt('Enter number ' + (i + 1) + ' of ' + (nums.length + 1));
  // place value (as a number) into the array
  nums[i] = new Number(input);
}
/* sum/average code */
// initialize array with 10 elements
var nums = new Array(10);
// prompt for 10 numbers
var input = prompt('Enter ' + (nums.length + 1) + ' numbers separated by commas:');
var values = input.split(',');
// check we have the right amount
if (values.length == nums.length){
  // iterate over the values
  for (var i = 0; i < nums.length; i++){
    // place the input (as a number) into the array
    nums[i] = new Number(values[i]);
  }
}
/* sum/average code */
<script>
  function average(){
    // initialize array with 10 elements
    var nums = new Array(10);
    // iterate over the elements
    for (var i = 0; i < nums.length; i++){
      // grab <input> based on id attribute
      var input = document.getElementById('num' + i);
      // insert the value (cast as a number) in to the array
      nums[i] = new Number(input.value); // case to number
    }
    /* sum/average code */
  }
</script>

<p>Enter 10 numbers:</p>
<input type="text" id="num0" />
<input type="text" id="num1" />
<input type="text" id="num2" />
<input type="text" id="num3" />
<input type="text" id="num4" />
<input type="text" id="num5" />
<input type="text" id="num6" />
<input type="text" id="num7" />
<input type="text" id="num8" />
<input type="text" id="num9" />

<button onclick="average()">Click to average</button>

How to correctly use pointers to compute average


By : user2209164
Date : March 29 2020, 07:55 AM
I wish did fix the issue. Testing that your pointer doesn't point into a \0 is fine when you work with strings. Here you have an array of ints and a length so you can't really use a destination point to stop incrementing the pointer. You need to use that len just like in your first snippet but instead of accessing the ith element of your array, you can still increment the pointer. Something like this :
code :
int compute_average(int *avgs, int len) {
  int sum = 0;
  for (int i = 0; i < len; i++)
    sum += *(avgs++);
  return (int)(sum / len);
}

Passing an array of pointers and return an array of values pointed by those pointers


By : Roberto Veloso
Date : March 29 2020, 07:55 AM
Does that help I want to write a function that passes an array of n pointers to float and returns a newly created array that contains those n float values. Here is the code: , Declaring b as
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