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How to print sub matrix in python?

By : lisaw
Date : October 16 2020, 03:08 PM
will be helpful for those in need Is there any short way in python to print sub matrix of a bigger matrix like this not using for loop? , For lists of lists, you can get your desired result like this:
code :
>>> [s[1:3] for s in matrix[1:3]]
[[6, 7], [10, 11]]
>>> [s[2:3] for s in matrix[1:4]]
[[7], [11], [15]]

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python 2D matrix simple logic works but matrix print logic doesnt show correct matrix

By : Prabhat Tamrakar
Date : March 29 2020, 07:55 AM
I hope this helps you . Must be something really stupid that I am doing but I can't seem to figure out what is going wrong here. I am an intermediate python user. , When you do
code :
Xr = [[0]*m]*n
m = 2
n = 2
Xr = [[0]*m]*n
print Xr
# [[0, 0], [0, 0]]
Xr[0][0] = 1
print Xr
# [[1, 0], [1, 0]]

In Python, given that there is a matrix, how do I print a slice of it?

By : Ravikant
Date : March 29 2020, 07:55 AM
This might help you The return value of as_matrix() is array of arrays. So following code should work:
code :
import pandas as pd
df = pd.read_csv("abc.csv")
matrix = df.as_matrix()
print(matrix[0]) # out put first row.
print(matrix[3:5] # output from 3 row up to 4 row.

Print all the non-zero element in a 2D matrix in Python

By : Ben Booton
Date : March 29 2020, 07:55 AM

How to print a matrix using Python

By : Rohit Dixit
Date : March 29 2020, 07:55 AM
wish helps you What you are getting is the correct representation of a matrix. You have created a list that contains 4 lists, each list containing 4 '0's. If you want to print it differently then you have some options, but what you are printing is the representation of the above mentioned data structure.

the out put is to print out the transpose of the matrix from the matrix you type in, but my code just print out the firs

By : utr
Date : March 29 2020, 07:55 AM
will be helpful for those in need You swap everything twice, so it ends up the same as when you started. Try this, I've commented the line that changes.
code :
int ChuyenVi(int A[100][100], int n)
    for(int i=0; i<n; i++)
        for(int j=0; j<i; j++) // <-- change here
            DoiGiaTri(A[i][j], A[j][i]);
    return 0;
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